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200203-1.cpp
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200203-1.cpp
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// https://leetcode-cn.com/problems/construct-binary-tree-from-inorder-and-postorder-traversal/
#include <cstdio>
#include <vector>
using namespace std;
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode(int x) : val(x), left(NULL), right(NULL) {}
};
TreeNode* create(initializer_list<int> a)
{
if (a.size() == 0) return NULL;
auto it = a.begin();
if (*it <= 0) return NULL;
TreeNode* t = new TreeNode(*it);
vector<TreeNode*> parents{t};
vector<TreeNode*> children;
++it;
for (size_t i = 0; it != a.end();) {
if (i < parents.size() * 2) {
TreeNode* c = (*it <= 0 ? NULL : new TreeNode(*it));
TreeNode* n = parents[i / 2];
if (i % 2 == 0) { n->left = c; } else { n->right = c; }
if (c) children.push_back(c);
++i; ++it;
} else {
parents = children;
children.clear();
i = 0;
}
}
return t;
}
void release(TreeNode* t)
{
if (t) {
release(t->left);
release(t->right);
delete t;
}
}
void print(TreeNode* t)
{
vector<TreeNode*> a{t};
int last = 0;
for (int i = 0;;) {
int end = a.size();
for (; i < end; ++i) {
a.push_back(a[i] ? a[i]->left : NULL);
a.push_back(a[i] ? a[i]->right : NULL);
if (a[i]) {
if (a[i]->right) last = a.size() - 1;
else if (a[i]->left) last = a.size() - 2;
}
}
if (last < end) break;
}
a.resize(last + 1);
printf("[ ");
for (auto e : a) {
if (e) {
printf("%d ", e->val);
} else {
printf("null ");
}
}
printf("]\n");
}
class Solution {
public:
TreeNode* buildTree(vector<int>& inorder, vector<int>& postorder) {
int n = postorder.size();
if (n == 0) return NULL;
return buildTree(&inorder[0], &postorder[0], n - 1, n - 1, n);
}
private:
TreeNode* buildTree(const int* p, const int* q, int a, int b, int n) {
if (n < 0) return NULL;
TreeNode* t = new TreeNode(q[b]);
int i = 0;
for (; i < n; ++i) {
if (p[a - i] == q[b]) break;
}
if (i + 1 < n) t->left = buildTree(p, q, a - (i + 1), b - (i + 1), n - (i + 1));
if (i > 0) t->right = buildTree(p, q, a, b - 1, i);
return t;
}
};
int main()
{
Solution s;
{
vector<int> inorder = {9,3,15,20,7};
vector<int> postorder = {9,15,7,20,3};
TreeNode* t = s.buildTree(inorder, postorder);
print(t); // answer: [ 3 9 20 null null 15 7 ]
release(t);
}
return 0;
}