-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathmain.c
248 lines (235 loc) · 6.46 KB
/
main.c
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
#include <stdio.h>
#include<stdlib.h>
#include "generator.h"
/*
1.透過討論版中廖政華 (LIAO,CHENG-HUA)
星期一5月10日 1:05
我原本也遇到一樣的問題,後來的做法是Q跟R不要混在一起sort,但還是要同時進行(也就是把sort Q和sort R寫在同一個merge sort裡),然後數intersection的方式如附圖
得到啟發:
善用merge sort的過程中開始數
如果用P點的排序把陣列變成兩塊,就可以避免在數交點的時候,需要在移動P點的時候,重新處理已經排序好的Q和R陣列中的資訊,像是array shift,同時也可以用原先得到的資訊
2. 版上有人提及如果每次merge sort 裡面的recursion都做一次malloc會TLE,應該直接一路傳過去,在外面宣告一次就好,受益匪淺
3. 在板上自己問的問題和助教的回信: 如何處理P點 (我想了很久才發現原來那麼簡單,應該是在推論的時候一直忘記考慮Qmax>Qmid>Rmid,所以只要descending 就好了,花了超久哈哈
*/
const int de=0;
const int de2=0;
const int de3=0;
const int de4=0;
const int de5=0;
const int de6=0;
const int io=0;
void print_data(int n,int *p,int *q,int *r){
printf("n:%d",n);
int i;
printf("\np:");
for(i=0;i<n;i++) printf("%d ",p[i]);
printf("\nq:");
for(i=0;i<n;i++) printf("%d ",q[i]);
printf("\nr:");
for(i=0;i<n;i++) printf("%d ",r[i]);
printf("\n");
}
void merge(int *arr,int *seq,int l0,int lm,int l1,int *temp,int *q){ //write seq->temp
int ptr1=l0,ptr2=lm+1,ptr3=l0,i;//換了方法要記得改ptr3起點,找了好久
if(l1==l0) temp[seq[l1]]=seq[l1];
else{
while(ptr1<=lm|ptr2<=l1){
if(de5) printf("ptr:%d %d %d\n",ptr1,ptr2,ptr3);
if(ptr1<=lm&ptr2<=l1){
if(arr[seq[ptr1]]<arr[seq[ptr2]]){
//if(de5) printf("ptr1 smaller:%d<%d\n",arr[seq[ptr1]],arr[seq[ptr2]]);
temp[ptr3]=seq[ptr1];
ptr1=ptr1+1;
}
else if(arr[seq[ptr1]]>arr[seq[ptr2]]){
//if(de5) printf("ptr1 larger:%d> ptr2=%d->seq[ptr]=%d->arr=%d\n",arr[seq[ptr1]],ptr2,seq[ptr2],arr[seq[ptr2]]);
temp[ptr3]=seq[ptr2];
ptr2=ptr2+1;
}//P點相同
else if(arr[seq[ptr1]]==arr[seq[ptr2]]){
if(q[seq[ptr1]]>q[seq[ptr2]]){
temp[ptr3]=seq[ptr1];
ptr1=ptr1+1;
}
else{
temp[ptr3]=seq[ptr2];
ptr2=ptr2+1;
}
}
ptr3=ptr3+1;
}
else if(ptr1<=lm){
while(ptr1<=lm){
temp[ptr3]=seq[ptr1];
ptr3=ptr3+1;
ptr1=ptr1+1;
}
}
else{
while(ptr2<=l1){
temp[ptr3]=seq[ptr2];
ptr2=ptr2+1;
ptr3=ptr3+1;
}
}
}
}
}
void merge_sort(int *p,int *seq,int l0,int l1,int *index3,int *q,int x){//seq has information, index is aux
int lm=(l0+l1)/2;
x=x*-1;
if(l1>l0){
merge_sort(p,index3,l0,lm,seq,q,x); //seq->index3
merge_sort(p,index3,lm+1,l1,seq,q,x); //seq->index3
merge(p,index3,l0,lm,l1,seq,q); //flow: index3->seq
}
else if(l1==l0){
if(x==-1) index3[l1]=seq[l1];//seq->index3
else seq[l1]=index3[l1];
}
}
void *merge_qr(int *q,int *r,int *seq,int *seq2,int qr0,int qrm,int qr1,long long *counter,int *temp,int *mark){
int i,ptr1=qr0,ptr2=qrm+1,ptr3=qr0,k;
long long j=0;
//j max=qr1-qrm
for(i=qr0;i<=qrm;i++){
if(j<qr1-qrm){
while(q[seq[i]]>=r[seq2[qrm+1+j]]){
j=j+1;
if(j>=qr1-qrm) break;
}
}
*counter=*counter+j;
if(de6){
printf("i=%d:\nq:\n",i);
for(k=qr0;k<=qrm;k++) printf("%d ",q[seq[k]]);
printf("\n");
for(k=qrm+1;k<=qr1;k++) printf("%d ",q[seq[k]]);
printf("\nr:\n");
for(k=qr0;k<=qrm;k++) printf("%d ",r[seq[k]]);
printf("\n");
for(k=qrm+1;k<=qr1;k++) printf("%d ",r[seq[k]]);
printf("\ncounter=%lld\n",*counter);
}
}
ptr1=qr0,ptr2=qrm+1,ptr3=qr0;
while(ptr1<=qrm|ptr2<=qr1){
if(ptr1<=qrm&ptr2<=qr1){
if(q[seq[ptr1]]<q[seq[ptr2]]){
temp[ptr3]=seq[ptr1];
ptr1=ptr1+1;
}
else{
temp[ptr3]=seq[ptr2];
ptr2=ptr2+1;
}
ptr3=ptr3+1;
}
else if(ptr1<=qrm){
while(ptr1<=qrm){
temp[ptr3]=seq[ptr1];
ptr3=ptr3+1;
ptr1=ptr1+1;
}
}
else{
while(ptr2<=qr1){
temp[ptr3]=seq[ptr2];
ptr2=ptr2+1;
ptr3=ptr3+1;
}
}
}
ptr1=qr0,ptr2=qrm+1,ptr3=qr0;
while(ptr1<=qrm|ptr2<=qr1){
if(ptr1<=qrm&ptr2<=qr1){
if(r[seq2[ptr1]]<r[seq2[ptr2]]){
mark[ptr3]=seq2[ptr1];
ptr1=ptr1+1;
}
else{
mark[ptr3]=seq2[ptr2];
ptr2=ptr2+1;
}
ptr3=ptr3+1;
}
else if(ptr1<=qrm){
while(ptr1<=qrm){
mark[ptr3]=seq2[ptr1];
ptr3=ptr3+1;
ptr1=ptr1+1;
}
}
else{
while(ptr2<=qr1){
mark[ptr3]=seq2[ptr2];
ptr2=ptr2+1;
ptr3=ptr3+1;
}
}
}
}
void merge_sort_qr(int *q,int *r,int *seq,int *seq2,int qr0,int qr1,long long *counter,int *temp,int *mark,int x){
int qrm=(qr0+qr1)/2;
x=x*(-1);
if(qr1>qr0){
merge_sort_qr(q,r,temp,mark,qr0,qrm,counter,seq,seq2,x);
merge_sort_qr(q,r,temp,mark,qrm+1,qr1,counter,seq,seq2,x);
merge_qr(q,r,temp,mark,qr0,qrm,qr1,counter,seq,seq2);
}
else if(qr1==qr0){
if(x==-1) temp[qr1]=seq[qr1];//seq->index3
else seq[qr1]=temp[qr1];
if(x==-1) mark[qr1]=seq2[qr1];//seq->index3
else seq2[qr1]=mark[qr1];
}
}
int main() {
int t;
if(io) scanf("%d",&t);
else{
generator.init();
t=generator.getT();
}
int i,j,k,count,temp;
long long *counter,c=0;
counter=&c;
while (t--) {
int n, *p, *q, *r,*seq;
count=0,*counter=0;
if(io){
scanf("%d",&n);
p=(int *)malloc(sizeof(int)*n);
q=(int *)malloc(sizeof(int)*n);
r=(int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++) scanf("%d",&p[i]);
for(i=0;i<n;i++) scanf("%d",&q[i]);
for(i=0;i<n;i++) scanf("%d",&r[i]);
}
else generator.getData(&n, &p, &q, &r);
for(i=0;i<n;i++){
if(q[i]<r[i]){
temp=q[i];
q[i]=r[i];
r[i]=temp;
}
}
int *mark=(int *)malloc(sizeof(int)*n);
seq=(int *)malloc(sizeof(int)*n);
int *index3=(int *)malloc(sizeof(int)*n),*temparr=(int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++) seq[i]=i;
merge_sort(p,seq,0,n-1,index3,q,1);
if(de4) for(i=0;i<n;i++) printf("%d ",p[seq[i]]);
int *seq2=(int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++) seq2[i]=seq[i];
int *seq1=(int *)malloc(sizeof(int)*n);
for(i=0;i<n;i++) seq1[i]=seq[i];
merge_sort_qr(q,r,seq1,seq2,0,n-1,counter,temparr,mark,1);
//fix repeat
int ptrp=0,s=0;
if(io) printf("\n\n");
printf("%lld\n",*counter);
if(io) printf("\n");
}
return 0;
}