X of a Kind in a Deck of Cards

X of a Kind in a Deck of Cards

You are given an integer array deck where deck[i] represents the number written on the ith card.
Partition the cards into one or more groups such that:
Each group has exactly x cards where x > 1, and
All the cards in one group have the same integer written on them.
Return true if such partition is possible, or false otherwise.
Example 1:

Input: deck = [1,2,3,4,4,3,2,1]
Output: true
Explanation: Possible partition [1,1],[2,2],[3,3],[4,4].
Example 2:

Input: deck = [1,1,1,2,2,2,3,3]
Output: false
Explanation: No possible partition.

class Solution {
    public boolean hasGroupsSizeX(int[] deck) {
        int N = deck.length;
        int[] count = new int[10000];
        for (int c: deck)
            count[c]++;

        List<Integer> values = new ArrayList();
        for (int i = 0; i < 10000; ++i)
            if (count[i] > 0)
                values.add(count[i]);

        search: for (int X = 2; X <= N; ++X)
            if (N % X == 0) {
                for (int v: values)
                    if (v % X != 0)
                        continue search;
                return true;
            }

        return false;
    }
}