-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathNextGreaterElementOne.java
88 lines (77 loc) · 2.8 KB
/
NextGreaterElementOne.java
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
package arrays.easy;
import java.util.Arrays;
import java.util.HashMap;
import java.util.Stack;
/***
* Problem 496 in Leetcode: https://leetcode.com/problems/next-greater-element-i/
*
* The next greater element of some element x in an array is the first greater element that is to the right of x in the same array.
* You are given two distinct 0-indexed integer arrays nums1 and nums2, where nums1 is a subset of nums2.
* For each 0 <= i < nums1.length, find the index j such that nums1[i] == nums2[j] and determine the next greater element of nums2[j] in nums2.
* If there is no next greater element, then the answer for this query is -1.
*
* Return an array ans of length nums1.length such that ans[i] is the next greater element as described above.
*
* Example 1:
* Input: nums1 = [4,1,2], nums2 = [1,3,4,2]
* Output: [-1,3,-1]
*
* Example 2:
* Input: nums1 = [2,4], nums2 = [1,2,3,4]
* Output: [3,-1]
*/
public class NextGreaterElementOne {
public static void main(String[] args) {
int[] nums1 = {4, 1, 2};
int[] nums2 = {1, 3, 4, 2};
System.out.println("Brute Force: " + Arrays.toString(nextGreaterElementBruteForce(nums1, nums2)));
System.out.println("Stack: " + Arrays.toString(nextGreaterElementStack(nums1, nums2)));
}
private static int[] nextGreaterElementBruteForce(int[] nums1, int[] nums2) {
int n = nums1.length;
int[] result = new int[n];
for (int i = 0; i < n; i++) {
result[i] = helperForBruteForce(nums2, nums1[i]);
}
return result;
}
private static int helperForBruteForce(int[] nums2, int value) {
int n = nums2.length;
for (int i = 0; i < n; i++) {
if (nums2[i] == value) {
if (i < n - 1) {
for (int j = i + 1; j < n; j++) {
if (nums2[j] > value) {
return nums2[j];
}
}
return -1;
}
return -1;
}
}
return -1;
}
private static int[] nextGreaterElementStack(int[] nums1, int[] nums2) {
HashMap<Integer, Integer> map = new HashMap<>();
Stack<Integer> stack = new Stack<>();
int n = nums2.length;
for (int i = n - 1; i >= 0; i--) {
while (!stack.isEmpty() && stack.peek() < nums2[i]) {
stack.pop();
}
int val = -1;
if (!stack.isEmpty()) {
val = stack.peek();
}
map.put(nums2[i], val);
stack.push(nums2[i]);
}
int m = nums1.length;
int[] result = new int[m];
for (int i = 0; i < m; i++) {
result[i] = map.getOrDefault(nums1[i], -1);
}
return result;
}
}