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Letter Combinations of a Phone Number.swift
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// https://leetcode.com/problems/letter-combinations-of-a-phone-number/description/?envType=study-plan-v2&envId=leetcode-75
/*
Given a string containing digits from 2-9 inclusive, return all possible letter combinations that the number could represent. Return the answer in any order.
A mapping of digits to letters (just like on the telephone buttons) is given below. Note that 1 does not map to any letters
*/
class Solution {
func letterCombinations(_ digits: String) -> [String] {
let phoneDict: [Int: [String]] = [
2: ["a", "b", "c"],
3: ["d", "e", "f"],
4: ["g", "h", "i"],
5: ["j", "k", "l"],
6: ["m", "n", "o"],
7: ["p", "q", "r", "s"],
8: ["t", "u", "v"],
9: ["w", "x", "y", "z"]
]
var result: [String] = []
for digit in digits {
let digitInt = Int(String(digit))!
if result.isEmpty {
result = phoneDict[digitInt]!
} else {
var temp: [String] = []
for char in phoneDict[digitInt]! {
for str in result {
temp.append(str + char)
}
}
result = temp
}
}
return result
}
}
// Bactracking approach:
class Solution {
private let phoneDict: [Character: [String]] = [
"2": ["a", "b", "c"],
"3": ["d", "e", "f"],
"4": ["g", "h", "i"],
"5": ["j", "k", "l"],
"6": ["m", "n", "o"],
"7": ["p", "q", "r", "s"],
"8": ["t", "u", "v"],
"9": ["w", "x", "y", "z"]
]
func letterCombinations(_ digits: String) -> [String] {
guard !digits.isEmpty else {
return []
}
var result = [String]()
backtrack("", digits, &result)
return result
}
func backtrack(_ combination: String, _ nextDigits: String, _ result: inout [String]) {
if nextDigits.isEmpty {
result.append(combination)
} else {
let digit = nextDigits.first!
for letter in phoneDict[digit]! {
backtrack(combination + letter, String(nextDigits.dropFirst()), &result)
}
}
}
}