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0222-count-complete-tree-nodes.rb
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# frozen_string_literal: true
# 222. Count Complete Tree Nodes
# https://leetcode.com/problems/count-complete-tree-nodes
# Medium
=begin
Given the root of a complete binary tree, return the number of the nodes in the tree.
According to Wikipedia, every level, except possibly the last, is completely filled in a complete binary tree, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h.
Design an algorithm that runs in less than O(n) time complexity.
Example 1:
Input: root = [1,2,3,4,5,6]
Output: 6
Example 2:
Input: root = []
Output: 0
Example 3:
Input: root = [1]
Output: 1
Constraints:
* The number of nodes in the tree is in the range [0, 5 * 104].
* 0 <= Node.val <= 5 * 104
* The tree is guaranteed to be complete.
=end
# Definition for a binary tree node.
# class TreeNode
# attr_accessor :val, :left, :right
# def initialize(val = 0, left = nil, right = nil)
# @val = val
# @left = left
# @right = right
# end
# end
# @param {TreeNode} root
# @return {Integer}
def count_nodes(root)
return 0 unless root
h = 0
node = root
h += 1 while node = node.left
return 1 if h.zero?
res = 2**h - 1
h -= 1
while h > 0
node = root.left
h.times { node = node.right }
if node
res += 2**h
root = root.right
else root = root.left
end
h -= 1
end
return res += 2 if root.right
res += 1 if root.left
res
end
require "test/unit"
class Test_count_nodes < Test::Unit::TestCase
def test_
assert_equal 6, count_nodes(tree_parser [1, 2, 3, 4, 5, 6])
assert_equal 0, count_nodes(tree_parser [])
assert_equal 1, count_nodes(tree_parser [1])
end
end
class TreeNode
attr_accessor :val, :left, :right
def initialize(val = 0, left = nil, right = nil)
@val = val
@left = left
@right = right
end
end
def tree_parser(arr)
return nil unless arr && !arr.empty?
root = TreeNode.new arr.shift
queue = [root]
until arr.empty?
node = queue.shift
(val = arr.shift).nil? ? nil : queue << node.left = TreeNode.new(val)
(val = arr.shift).nil? ? nil : queue << node.right = TreeNode.new(val)
end
root
end