-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy pathDay26. ContiguousArray.cpp
51 lines (43 loc) · 1.15 KB
/
Day26. ContiguousArray.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
/*
Given a binary array, find the maximum length of a contiguous subarray with equal number of 0 and 1.
Example 1:
Input: [0,1]
Output: 2
Explanation: [0, 1] is the longest contiguous subarray with equal number of 0 and 1.
Example 2:
Input: [0,1,0]
Output: 2
Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1.
Note: The length of the given binary array will not exceed 50,000.
*/
class Solution {
public:
int findMaxLength(vector<int>& nums) {
int n=nums.size();
if(n<=1) return 0;
vector<int> arr(n,-1);
arr[0]= (nums[0]==0)? -1:1 ;
for(int i=1;i<n;i++)
{
arr[i] = arr[i-1] + ((nums[i]==0)? -1 : 1) ;
}
int sol=0;
unordered_map<int,int> mp;
for(int i=0;i<n;i++)
{
if(arr[i]==0) sol = i+1;
else
{
if(mp.find(arr[i])==mp.end())
{
mp[arr[i]]=i;
}
else
{
sol=max(sol,i-mp[arr[i]]);
}
}
}
return sol;
}
};