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GFG_CheckIfLLisPalindrome.cpp
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GFG_CheckIfLLisPalindrome.cpp
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/*
https://practice.geeksforgeeks.org/problems/check-if-linked-list-is-pallindrome/1#
Check if Linked List is Palindrome
*/
// { Driver Code Starts
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <stack>
using namespace std;
/* Link list Node */
struct Node {
int data;
struct Node *next;
Node(int x) {
data = x;
next = NULL;
}
};
// } Driver Code Ends
/*
struct Node {
int data;
struct Node *next;
Node(int x) {
data = x;
next = NULL;
}
};
*/
class Solution{
public:
//Function to check whether the list is palindrome.
bool isPalindrome(Node *head)
{
if(!head || !head->next)
return true;
//finding mid element
Node* mid = nullptr;
Node* slow = head, *fast=head->next;
while(fast && fast->next)
{
slow = slow->next;
fast = fast->next->next;
}
mid = slow;
Node *list2 = mid->next;
// reversing the second list
Node *prev = nullptr, *cur=list2, *cnxt = nullptr;
while(cur)
{
cnxt = cur->next;
cur->next = prev;
prev = cur;
cur = cnxt;
}
list2 = prev;
mid->next = nullptr; // 1 -> * || 2 || <-1, 1->2->* || *<-3<-4
// checing the palindrome
while(list2)
{
if(list2->data != head->data)
return false;
list2 = list2->next;
head = head->next;
}
return true;
}
};
// { Driver Code Starts.
/* Driver program to test above function*/
int main()
{
int T,i,n,l,firstdata;
cin>>T;
while(T--)
{
struct Node *head = NULL, *tail = NULL;
cin>>n;
// taking first data of LL
cin>>firstdata;
head = new Node(firstdata);
tail = head;
// taking remaining data of LL
for(i=1;i<n;i++)
{
cin>>l;
tail->next = new Node(l);
tail = tail->next;
}
Solution obj;
cout<<obj.isPalindrome(head)<<endl;
}
return 0;
}
// } Driver Code Ends