难度:Easy
Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters.
Please note that the string does not contain any non-printable characters.
Example:
Input: "Hello, my name is John"
Output: 5
以空格分割,然后找出最后一个空格之后是否有单词即可。
class Solution {
public:
int countSegments(string s) {
int res=0;
bool ischar=false;
if(s.empty()) return res;
if(s.size()==1) return s[0]!=' ';
for(int i=1;i<s.length();i++)
if((s[i]==' ') && (s[i-1] !=' '))
{
res++;
//cout<<" "<< i<< res<<" "<<s[i]<<" "<<s[i-1]<<endl;
ischar=false;
}
else if(s[i]!=' ')
ischar=true;
return res+ischar;
}
};
执行用时 :0 ms, 在所有 C++ 提交中击败了100.00%的用户
内存消耗 :8.2 MB, 在所有 C++ 提交中击败了90.29%的用户