trying to fixed aligned 2E1

_problems/unit-02/E-cdf-of-a-continuous-rv/1.md

@@ -15,11 +15,11 @@ Let F(x) be the CDF of X. Based on the given information, $F(x) = 0$ for $x \le
 For $x \ge 0$, $F(x)$ can be found as the following    
 
 $$\begin{aligned}
-F(x)&= \int_{-\infty}^x \frac{u}{2}du \\
-&= \int_{-\infty}^0 f(u)du + \int_{0}^x f(u)du \\
-&= 0 + \int_{0}^{x}\frac{u}{2}du\\ 
-&= \frac{x^2}{4}\\
-\end{aligned}$$
+F(x)&= \int_{-\infty}^x \frac{u}{2}du \\\\
+&= \int_{-\infty}^0 f(u)du + \int_{0}^x f(u)du \\\\
+&= 0 + \int_{0}^{x}\frac{u}{2}du\\\\
+&= \frac{x^2}{4}
+\\end{aligned}$$
 
 (b) $$\begin{aligned}
 P(X<1) = F(1) = \frac{1^2}{4} = \frac{1}{4}