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Copy pathMusic Store Data Analysis Using SQL.sql
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Music Store Data Analysis Using SQL.sql
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-- Q1: Who is the senior most employee based on job title ?
SELECT * FROM employee
ORDER BY levels DESC
LIMIT 1;
-- Q2: Which countries have the most Invoices ?
SELECT COUNT(*) AS c, billing_country
from invoice
GROUP BY billing_country
ORDER BY c DESC;
-- Q3: What are top 3 values of total invoice ?
SELECT total FROM invoice
ORDER BY total DESC
LIMIT 3;
-- Q4: Which city has the best customers ?
-- we would like to throw a promotional Music Festival in the city we made the most money.
-- Write a query that returns one city that has the highest sum of invoice totals.
-- Return both the city name & sum of all invoice totals ?
SELECT SUM(total) AS invoice_total, billing_city
FROM invoice
GROUP BY billing_city
ORDER BY invoice_total DESC;
-- Q5: Who is the best customer? The customer who has spent the most money will be declared the best customer.
-- Write a query that returns the person who has spent the most money ?
SELECT customer.customer_id, customer.first_name, customer.last_name, SUM(invoice.total) AS total
FROM customer
JOIN invoice ON customer.customer_id = invoice.customer_id
GROUP BY customer.customer_id
ORDER BY total DESC
LIMIT 1;
-- Q6: Write query to return the email, first name, last name, & Genre of all Rock Music listeners.
-- Return your list ordered alphabetically by email starting with A ?
SELECT DISTINCT email, first_name, Last_name
FROM customer
JOIN invoice ON customer.customer_id = invoice.customer_id
JOIN invoice_line ON invoice.invoice_id = invoice_line.invoice_id
WHERE track_id IN(
SELECT track_id FROM track
JOIN genre ON track.genre_id = genre.genre_id
WHERE genre.name LIKE 'Rock'
)
ORDER BY email;
-- Q7: Let's invite the artists who have written the most rock music in our dataset.
-- Write a query that returns the Artist name and total track count of the top 10 rock bands ?
SELECT artist.artist_id, artist.name, COUNT(artist.artist_id) AS number_of_songs
FROM track
JOIN album ON album.album_id = track.album_id
JOIN artist ON artist.artist_id = album.artist_id
JOIN genre ON genre.genre_id = track.genre_id
WHERE genre.name LIKE 'Rock'
GROUP BY artist.artist_id
ORDER BY number_of_songs DESC
LIMIT 10;
-- Q8: Return all the track names that have a song length longer than the average song length.
-- Return the Name and Milliseconds for each track.
-- Order by the song length with the longest songs listed first ?
SELECT NAME, milliseconds
FROM track
WHERE milliseconds > (
SELECT AVG(milliseconds) AS avg_track_length
FROM track)
ORDER BY milliseconds DESC;
-- Q9: Find how much amount spent by each customer on artists?
-- Write a query to return customer name, artist name and total spent ?
WITH best_selling_artist AS (
SELECT
artist.artist_id AS artist_id,
artist.name AS artist_name,
SUM(invoice_line.unit_price * invoice_line.quantity) AS total_sales
FROM
invoice_line
JOIN
track ON track.track_id = invoice_line.track_id
JOIN
album ON album.album_id = track.album_id
JOIN
artist ON artist.artist_id = album.artist_id
GROUP BY
artist.artist_id, artist.name
ORDER BY
total_sales DESC
LIMIT 1
)
SELECT c.customer_id, c.first_name, c.last_name, bsa.artist_name,
SUM(il.unit_price*il.quantity) AS amount_spent
FROM invoice i
JOIN customer c ON c.customer_id = i.customer_id
JOIN invoice_line il ON il.invoice_id = i.invoice_id
JOIN track t ON t.track_id = il.track_id
JOIN album alb ON alb.album_id = t.album_id
JOIN best_selling_artist bsa ON bsa.artist_id = alb.artist_id
GROUP BY 1,2,3,4
ORDER BY 5 DESC;
-- Q10: We want to find out the most popular music Genre for each country.
-- We determine the most popular genre as the genre with the highest amount of purchases.
-- Write a query that returns each country along with the top Genre.
-- For countries where the maximum number of purchases is shared return all Genres ?
WITH popular_genre AS
(
SELECT COUNT(invoice_line.quantity) AS purchases,
customer.country, genre.name, genre.genre_id,
ROW_NUMBER() OVER (PARTITION BY customer.country ORDER BY COUNT(invoice_line.quantity) DESC) AS RowNo
FROM invoice_line
JOIN invoice ON invoice.invoice_id = invoice_line.invoice_id
JOIN customer ON customer.customer_id = invoice.customer_id
JOIN track ON track.track_id = invoice_line.track_id
JOIN genre ON genre.genre_id = track.genre_id
GROUP BY 2,3,4
ORDER BY 2 ASC, 1 DESC
)
SELECT * FROM popular_genre WHERE RowNo <= 1;
-- Q11: Write a query that determines the customer that has spent the most on music for each country.
-- Write a query that returns the country along with the top customer and how much they spent.
-- For countries where the top amount spent is shared, provide all customers who spent this amount?
WITH Customter_with_country AS (
SELECT customer.customer_id,first_name,last_name,billing_country,SUM(total) AS total_spending,
ROW_NUMBER() OVER(PARTITION BY billing_country ORDER BY SUM(total) DESC) AS RowNo
FROM invoice
JOIN customer ON customer.customer_id = invoice.customer_id
GROUP BY 1,2,3,4
ORDER BY 4 ASC,5 DESC)
SELECT * FROM Customter_with_country WHERE RowNo <= 1;