Only first line of a function’s output gets passed through pipe

[sultanqasim]

When you pipe the output of a multi-line function (in a shell script), only the first line’s output goes into the pipe, and the rest goes direct to stdout. This is the second issue I had pointed out in #859. The difference between quoted and unquoted versions of the variable I pointed out earlier was a red herring because echoing an unquoted multi-line variable is supposed to replace the newlines with spaces when being displayed.

Reproduction script:

#! /bin/sh

foo() {
        printf "baa "
        printf "caa "
        printf "daa "
}

foo | tr 'a' 'z'
printf "\n"

Expected output:

bzz czz dzz

a-Shell output:

caa daa bzz

[holzschu]

Thank you for opening this issue. Unlike #859, this one is going to take a longer time to fix. I know roughly where it happens, but not why. The standard output that is piped into the command is closed after the first line of the function; trying to keep it open results in a lot of undesirable behaviour in other places. I'll keep working on it, but it's a tough one.