You are given a 0-indexed string s
of even length n
. The string consists of exactly n / 2
opening brackets '['
and n / 2
closing brackets ']'
.
A string is called balanced if and only if:
- It is the empty string, or
- It can be written as
AB
, where bothA
andB
are balanced strings, or - It can be written as
[C]
, whereC
is a balanced string.
You may swap the brackets at any two indices any number of times.
Return the minimum number of swaps to make s
balanced.
Input: s = "][][" Output: 1 Explanation: You can make the string balanced by swapping index 0 with index 3. The resulting string is "[[]]".
Input: s = "]]][[[" Output: 2 Explanation: You can do the following to make the string balanced: - Swap index 0 with index 4. s = "[]][][". - Swap index 1 with index 5. s = "[[][]]". The resulting string is "[[][]]".
Input: s = "[]" Output: 0 Explanation: The string is already balanced.
n == s.length
2 <= n <= 106
n
is even.s[i]
is either'['
or']'
.- The number of opening brackets
'['
equalsn / 2
, and the number of closing brackets']'
equalsn / 2
.
impl Solution {
pub fn min_swaps(s: String) -> i32 {
let mut count = 0;
let mut ret = 0;
for c in s.chars() {
if c == '[' {
count += 1;
} else if c == ']' && count > 0 {
count -= 1;
} else {
count += 1;
ret += 1;
}
}
ret
}
}