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enisbeziau committed Dec 24, 2023
2 parents 2a38832 + c78f2c8 commit eace5e9
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Expand Up @@ -130,7 +130,11 @@ <h2>2. Recherche de cycles non triviaux</h2>
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Ainsi \(B=3A+1\), qui est pair donc \(C=\displaystyle \frac{B}{2}=\frac{3A+1}{2}\). Puisque \(C \to A\) et \(C \gt
A\), \(C\) est pair et vaut
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\(\displaystyle \frac{B}{2}=\frac{1}{2}\left(\frac{3A+1}{2}\right)=\frac{3A+1}{4}\)
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\(\displaystyle \frac{B}{2}=\frac{1}{2}(\frac{3A+1}{2})=\frac{3A+1}{4}\)
>>>>>>> c78f2c8fbb69181fc668d0802d0e70959759f29d
<br>
Résolvons maintenant l'équation d'inconnue \(A\in \mathbb N^*\) afin de déduire les valeurs de \(A, B,
C\) tels que le cycle existe.
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