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Copy path88. Merge Sorted Array.java
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88. Merge Sorted Array.java
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/*
You are given two integer arrays nums1 and nums2, sorted in non-decreasing order, and two integers m and n, representing the number of elements in nums1 and nums2 respectively.
Merge nums1 and nums2 into a single array sorted in non-decreasing order.
The final sorted array should not be returned by the function, but instead be stored inside the array nums1. To accommodate this, nums1 has a length of m + n, where the first m elements denote the elements that should be merged, and the last n elements are set to 0 and should be ignored. nums2 has a length of n.
Example 1:
Input: nums1 = [1,2,3,0,0,0], m = 3, nums2 = [2,5,6], n = 3
Output: [1,2,2,3,5,6]
Explanation: The arrays we are merging are [1,2,3] and [2,5,6].
The result of the merge is [1,2,2,3,5,6] with the underlined elements coming from nums1.
Example 2:
Input: nums1 = [1], m = 1, nums2 = [], n = 0
Output: [1]
Explanation: The arrays we are merging are [1] and [].
The result of the merge is [1].
Example 3:
Input: nums1 = [0], m = 0, nums2 = [1], n = 1
Output: [1]
Explanation: The arrays we are merging are [] and [1].
The result of the merge is [1].
Note that because m = 0, there are no elements in nums1. The 0 is only there to ensure the merge result can fit in nums1.
Constraints:
nums1.length == m + n
nums2.length == n
0 <= m, n <= 200
1 <= m + n <= 200
-109 <= nums1[i], nums2[j] <= 109
*/
//solution
class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
m = m+n;
for (int i = 0; i < n; i++) {
nums1[i + m - n] = nums2[i];
}
insertionSort(nums1);
}
public void insertionSort(int[] arr){
for (int i = 0; i < arr.length - 1; i++) {
for (int j = i+1; j > 0 ; j--) {
if(arr[j] < arr[j-1]){
swapArray(arr,j,j-1);
}else {
break;
}
}
}
}
public void swapArray(int[] arr,int first,int second){
int temp = arr[first];
arr[first] = arr[second];
arr[second] = temp;
}
}