1365. How Many Numbers Are Smaller Than the Current Number.java

/*
Example 1:

Input: nums = [8,1,2,2,3]
Output: [4,0,1,1,3]
Explanation: 
For nums[0]=8 there exist four smaller numbers than it (1, 2, 2 and 3). 
For nums[1]=1 does not exist any smaller number than it.
For nums[2]=2 there exist one smaller number than it (1). 
For nums[3]=2 there exist one smaller number than it (1). 
For nums[4]=3 there exist three smaller numbers than it (1, 2 and 2).
Example 2:

Input: nums = [6,5,4,8]
Output: [2,1,0,3]
Example 3:

Input: nums = [7,7,7,7]
Output: [0,0,0,0]
 

Constraints:

2 <= nums.length <= 500
0 <= nums[i] <= 100
*/

//Solution
class Solution {
    public int[] smallerNumbersThanCurrent(int[] nums) {
        int[] arr = new int[nums.length];
        for (int i = 0; i < nums.length; i++) {
            int x = 0;
            for (int j = 0; j < nums.length; j++) {
                if(nums[i] > nums[j]){
                    x++;
                }
            }
            arr[i] = x;
        }
        
        return arr;
        
    }
}