How to handle spread/variadic argument for a function?

[ekaradon]

I try to reproduce the following type:

function foo(...parameters: string[]) {
}

But I don't see a way to do it with zod. 🤔
I've seen this discussion: #1282
But I can't make it match the signature from this function here. Is it possible? I know that I could just use a single parameter as an array of string but it make things less readable in my case.

[JacobWeisenburger]

I reopened variadic args function #1282. Hopefully we can get a better answer.

[TyIsI]

Just in case anyone stumbles upon this discussion.

z.function(z.tuple([]).rest(z.string()), zBoolean) does the trick for me.