Attempt 1: Use recursion that passes the parent value and the current count
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
private int maxCount ;
public int longestConsecutive (TreeNode root ) {
maxCount = 1 ;
longestConsecutiveRecursion (root .left , root .val , 1 );
longestConsecutiveRecursion (root .right , root .val , 1 );
return maxCount ;
}
private void longestConsecutiveRecursion (TreeNode root , int parentVal , int currCount ) {
if (root == null ) {
return ;
}
if (root .val == parentVal + 1 ) {
currCount ++;
maxCount = Math .max (maxCount , currCount );
} else {
currCount = 1 ;
}
longestConsecutiveRecursion (root .left , root .val , currCount );
longestConsecutiveRecursion (root .right , root .val , currCount );
}
}
Runtime: 0 ms (Beats: 100.00%)
Memory: 46.08 MB (Beats: 29.55%)