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scrolld.s
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;; scroll down
.globl _scrolld
.globl _cdtc_screen_basic__table_hl_source
.globl _cdtc_screen_basic__table_hl_dest
.globl _cdtc_screen_basic__table_hl
.globl _screen_offset
;;Pensarse seriamente usar como destino un backbuffer y usar doble buffer. A ello voy.
_scrolld::
ld a,l
or a
ret z ;;if OPCODE_N =0 return
ld a,l
;add a,a ;;bY = OPCODE_N * 2
ld h,#128 ;; i = 128
ld c,#0
;ld iy,#_cdtc_screen_basic__table_hl_dest
;ld iy,#_cdtc_screen_basic__table_hl_source
;ld de,1(iy)
loop:
dec h
cp h
jp z,loop1
ld l,h
ld iy,#_cdtc_screen_basic__table_hl_dest
ld h,1(iy)
;ld h, #_cdtc_screen_basic__table_hl >> 8 ; MSB table
ld d,(hl) ; read MSB
inc h ; LSB table
ld e,(hl) ; read LSB || DE tiene comienzo linea destino
ld h,l
push hl
ld b,a
sbc hl,bc
;;ld (#_sadd1+1),hl
ld l,h
ld iy,#_cdtc_screen_basic__table_hl_source
ld h,1(iy)
;ld h, #_cdtc_screen_basic__table_hl >> 8 ; MSB table
push de
ld d,(hl) ; read MSB
inc h ; LSB table
ld e,(hl) ; read LSB || DE tiene comienzo linea origen
ex de,hl ;HL tiene comienzo linea origen
pop de ;DE tiene comienzo linea destino
push hl
ldi
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pop de
pop hl
push hl
dec h
ld l,h
ld iy,#_cdtc_screen_basic__table_hl_dest
ld h,1(iy)
;ld h, #_cdtc_screen_basic__table_hl >> 8 ; MSB table
push de
ld d,(hl) ; read MSB
inc h ; LSB table
ld e,(hl) ; read LSB || DE tiene comienzo linea destino ¿¿mejor calculando linea destino como |set 3,d|, según https://www.cpcwiki.eu/forum/programming/sprites-tiles-and-other-superfast-screen-output-approaches/msg225567/#msg225567
pop hl
ldi
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pop hl
dec h
cp h
jp nz,loop
loop1:
dec a
;ret z
ld l,a
ld iy,#_cdtc_screen_basic__table_hl_dest
ld h,1(iy)
;ld h, #_cdtc_screen_basic__table_hl >> 8 ; MSB table
ld d,(hl) ; read MSB
inc h ; LSB table
ld e,(hl) ; read LSB || DE tiene comienzo linea destino
ex de,hl
ld bc,#0
ld de,#64
ld (#_stack+1), sp
add hl, de
di ; esto mete lag y/o jiter a la interrupción?
ld sp, hl
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
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push bc
push bc
push bc
push bc
push bc
push bc
cp #0
jp z,out
dec a
ld l,a
ld iy,#_cdtc_screen_basic__table_hl_source ;;¿haría falta borrar la linea de origen?
ld h,1(iy)
;ld h, #_cdtc_screen_basic__table_hl >> 8 ; MSB table
ld d,(hl) ; read MSB
inc h ; LSB table
ld e,(hl) ; read LSB || DE tiene comienzo linea origen
ex de,hl ;HL tiene comienzo linea origen
;ld bc,#0
ld de,#64
add hl, de
ld sp, hl
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
push bc
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push bc
push bc
push bc
push bc
push bc
push bc
out:
_stack:
ld sp,#0
ei
cp #0
ret z
jp loop1