Update README.md

Signed-off-by: Fabiana Campanari <fabicampanari@gmail.com>

README.md

@@ -148,15 +148,15 @@ Result: The limit of the function as ( x ) approaches 1 is simply $$\frac{1}{4}$
 
 In this case, we can use L'Hôpital's rule, as the limit is of the form \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\) when \(x\) tends to infinity.
 
-\[
+$$\
 \begin{align*}
 \lim_{{x \to \infty}} \frac{{x^2}}{{2x^2 - x}} &= \lim_{{x \to \infty}} \frac{{\frac{d}{dx}[x^2]}}{{\frac{d}{dx}[2x^2 - x]}} \\
 &= \lim_{{x \to \infty}} \frac{{2x}}{{4x - 1}} \\
 &= \lim_{{x \to \infty}} \frac{{2}}{{4 - \frac{1}{x}}} \\
 &= \frac{2}{4} \\
 &= \frac{1}{2}
 \end{align*}
-\]
+\$$