Merge pull request #329 from Quantum-Software-Development/FabianaCamp…

…anari-patch-1

Update README.md

README.md

@@ -149,6 +149,8 @@ In this case, we can use L'Hôpital's rule, as the limit is of the form \(\frac{
 \lim_{{x \to \infty}} \frac{{x^2}}{{2x^2 - x}} &= \lim_{{x \to \infty}} \frac{{\frac{d}{dx}[x^2]}}{{\frac{d}{dx}[2x^2 - x]}} \\
 &= \lim_{{x \to \infty}} \frac{{2x}}{{4x - 1}} \\
 &= \lim_{{x \to \infty}} \frac{{2}}{{4 - \frac{1}{x}}} \\
+&= \frac{2}{4} \\
+