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String.prototype.replace() without RegExp #20

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sleirsgoevy opened this issue May 5, 2017 · 0 comments
Open

String.prototype.replace() without RegExp #20

sleirsgoevy opened this issue May 5, 2017 · 0 comments

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@sleirsgoevy
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The first argument of String.prototype.replace() is actually interpreted as a Lua search pattern, not as a string.
For example, this code
console.log("String.prototype.replace()".replace("$", " is buggy"))
prints String.prototype.replace() is buggy, while it should just print String.prototype.replace().

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