2023-06-04

0002.两数相加/0002-两数相加 2.py

@@ -0,0 +1,39 @@
+# Definition for singly-linked list.
+# class ListNode(object):
+#     def __init__(self, x):
+#         self.val = x
+#         self.next = None
+
+class Solution(object):
+    def addTwoNumbers(self, l1, l2):
+        """
+        :type l1: ListNode
+        :type l2: ListNode
+        :rtype: ListNode
+        """
+        if self.getLength(l1) < self.getLength(l2):
+            l1, l2 = l2, l1
+        head = l1
+        while(l2):
+            l1.val += l2.val
+            l1 = l1.next
+            l2 = l2.next
+
+        p = head
+        while(p):
+            if p.val > 9:
+                p.val -= 10
+                if p.next:
+                    p.next.val += 1
+                else:
+                    p.next = ListNode(1)
+            p = p.next   
+        return head
+
+
+    def getLength(self, l):
+        tmp = 0
+        while(l):
+            tmp += 1
+            l = l.next
+        return tmp

0009.回文数/0009-回文数 2.py

@@ -0,0 +1,17 @@
+class Solution(object):
+    def isPalindrome(self, x):
+        """
+        :type x: int
+        :rtype: bool
+        """
+        #2019.6.1
+        xx = x
+        if x < 0:
+            return False
+
+        reverse = 0
+        while x > 0:
+            x, tmp = divmod(x, 10)
+            reverse = reverse * 10 + tmp
+
+        return reverse == xx

0019.删除链表的倒数第N个结点/0019-删除链表的倒数第N个结点.py

@@ -0,0 +1,28 @@
+# Definition for singly-linked list.
+# class ListNode:
+#     def __init__(self, val=0, next=None):
+#         self.val = val
+#         self.next = next
+class Solution:
+    def removeNthFromEnd(self, head: Optional[ListNode], n: int) -> Optional[ListNode]:
+        l = 0
+        p = head
+        while p:
+            l += 1
+            p = p.next
+
+        count = l - n + 1
+
+        dummy = ListNode(-1)
+        dummy.next = head
+        cur = -1
+        p = dummy
+        while p:
+            cur += 1
+            if cur == count - 1:
+                node_to_be_deleted = p.next
+                p.next = node_to_be_deleted.next
+                break
+            p = p.next
+
+        return dummy.next

0020.有效的括号/0020-有效的括号 2.py

@@ -0,0 +1,16 @@
+class Solution(object):
+    def isValid(self, s):
+        """
+        :type s: str
+        :rtype: bool
+        """
+        dic = {")": "(", "]":"[", "}":"{"}
+        stack = []
+        for ch in s:
+            if ch in ["(", "[", "{"]:
+                stack.append(ch)
+            else:
+                if not stack or dic[ch] != stack[-1]:
+                    return False
+                stack.pop()
+        return len(stack) == 0 

0021.合并两个有序链表/0021-合并两个有序链表 2.py

@@ -0,0 +1,33 @@
+# Definition for singly-linked list.
+# class ListNode(object):
+#     def __init__(self, x):
+#         self.val = x
+#         self.next = None
+
+class Solution(object):
+    def mergeTwoLists(self, l1, l2):
+        """
+        :type l1: ListNode
+        :type l2: ListNode
+        :rtype: ListNode
+        """
+        dummy = ListNode(-1)
+
+        p = dummy
+
+        while l1 and l2:
+            if l1.val <= l2.val:
+                p.next = ListNode(l1.val)
+                l1 = l1.next
+            else:
+                p.next = ListNode(l2.val)
+                l2 = l2.next
+            p = p.next
+
+        if l1:
+            p.next = l1
+
+        if l2:
+            p.next = l2
+
+        return dummy.next

0022.括号生成/0022-括号生成 2.py

@@ -0,0 +1,22 @@
+class Solution(object):
+    def generateParenthesis(self, n):
+        """
+        :type n: int
+        :rtype: List[str]
+        """
+
+        res = []
+
+        def dfs(tmp, left, right):
+            if len(tmp) == 2 * n:
+                res.append(tmp)
+
+            if left:
+                dfs(tmp + "(", left - 1, right)
+            if right > left:
+                dfs(tmp + ")", left, right - 1)
+
+
+        dfs("", n, n)
+        return res
+

0024.两两交换链表中的节点/0024-两两交换链表中的节点 2.py

@@ -0,0 +1,26 @@
+# Definition for singly-linked list.
+# class ListNode(object):
+#     def __init__(self, x):
+#         self.val = x
+#         self.next = None
+
+class Solution(object):
+    def swapPairs(self, head):
+        """
+        :type head: ListNode
+        :rtype: ListNode
+        """
+        if not head or not head.next:
+            return head
+        dummy = ListNode(1)
+        dummy.next = head
+
+        first = head
+        second = head.next
+
+        tail = second.next
+        first.next = self.swapPairs(tail)
+        second.next = first
+        dummy.next = second
+
+        return dummy.next

0026.删除有序数组中的重复项/0026-删除有序数组中的重复项.py

@@ -0,0 +1,10 @@
+class Solution:
+    def removeDuplicates(self, nums: List[int]) -> int:
+        visited = set()
+        index = 0
+        for num in nums:
+            if num not in visited:
+                visited.add(num)
+                nums[index] = num
+                index += 1
+        return index

0027.移除元素/0027-移除元素 2.py

@@ -0,0 +1,21 @@
+class Solution(object):
+    def removeElement(self, nums, val):
+        """
+        :type nums: List[int]
+        :type val: int
+        :rtype: int
+        """
+        nums.sort()
+        for i, num in enumerate(nums):
+            if num == val:
+                j = i + 1
+                while(j < len(nums) and nums[j] == num):
+                    j += 1
+                t = j
+                while(j < len(nums)):
+                    nums[i] = nums[j]
+                    i += 1
+                    j += 1
+                return i
+
+

0028.找出字符串中第一个匹配项的下标/0028-找出字符串中第一个匹配项的下标.py

@@ -0,0 +1,5 @@
+class Solution:
+    def strStr(self, haystack: str, needle: str) -> int:
+        if needle not in haystack:
+            return -1
+        return haystack.index(needle)

0034.在排序数组中查找元素的第一个和最后一个位置/0034-在排序数组中查找元素的第一个和最后一个位置 2.py

@@ -0,0 +1,56 @@
+class Solution(object):
+    def searchRange(self, nums, target):
+        """
+        :type nums: List[int]
+        :type target: int
+        :rtype: List[int]
+        """
+        lo, hi = 0, len(nums) - 1
+
+        while lo <= hi:
+
+            mid = (lo + hi) // 2
+            # print lo, hi, mid, nums
+            if nums[mid] == target:
+                break
+            elif nums[mid] < target:
+                lo = mid + 1
+            else:
+                hi = mid - 1
+
+        if lo > hi:
+            return [-1, -1]
+        midposition = mid
+        leftside, rightside = midposition, midposition
+        #ÕÒ×ó±ß½ç
+        # print 1
+        lo, hi = 0, midposition
+        while lo <= hi:
+            # print lo, hi, mid
+            mid = (lo + hi) // 2
+            if nums[mid] < target:
+                lo = mid + 1
+            elif nums[mid] == target:
+                if mid == 0 or (mid - 1 >= 0 and nums[mid - 1] < target):
+                    leftside = mid
+                    break
+                else:
+                    hi = mid - 1
+        # print 1      
+        #ÕÒÓұ߽ç
+        lo, hi = midposition, len(nums) - 1
+        while lo <= hi:
+            mid = (lo + hi) // 2
+            if nums[mid] > target:
+                hi = mid - 1
+            elif nums[mid] == target:
+                if mid == len(nums) - 1 or (mid + 1 < len(nums) and nums[mid + 1] > target):
+                    rightside = mid
+                    break
+                else:
+                    lo = mid + 1
+
+        return [leftside, rightside]
+
+
+

0035.搜索插入位置/0035-搜索插入位置 2.py

@@ -0,0 +1,18 @@
+class Solution(object):
+    def searchInsert(self, nums, target):
+        """
+        :type nums: List[int]
+        :type target: int
+        :rtype: int
+        """
+        left, right = 0, len(nums) - 1
+        while left <= right:
+            mid = (left + right) // 2
+
+            if nums[mid] == target:
+                return mid
+            elif nums[mid] > target:
+                right = mid - 1
+            elif nums[mid] < target:
+                left = mid + 1
+        return left

0036.有效的数独/0036-有效的数独 2.py

@@ -0,0 +1,15 @@
+class Solution:
+    def isValidSudoku(self, board: List[List[str]]) -> bool:
+        row = defaultdict(set)
+        col = defaultdict(set)
+        square = defaultdict(set)
+        for i in range(9):
+            for j in range(9):
+                if board[i][j].isdigit():
+                    if board[i][j] in row[i] or board[i][j] in col[j] or board[i][j] in square[(i // 3, j // 3)]:
+                        return False
+                    else:
+                        row[i].add(board[i][j])
+                        col[j].add(board[i][j])
+                        square[(i // 3, j // 3)].add(board[i][j])
+        return True

0045.跳跃游戏II/0045-跳跃游戏II.py

@@ -0,0 +1,9 @@
+class Solution:
+    def jump(self, nums: List[int]) -> int:
+        dp = [float("inf") for _  in nums]
+        dp[0] = 0
+        for i, num in enumerate(nums):
+            for j in range(1, 1 + num):
+                if i + j < len(nums):
+                    dp[i + j] = min(dp[i + j], dp[i] + 1)
+        return dp[-1]

0046.全排列/0046-全排列 2.py

@@ -0,0 +1,16 @@
+class Solution(object):
+    def permute(self, nums):
+        """
+        :type nums: List[int]
+        :rtype: List[List[int]]
+        """
+        res = []
+        def dfs(tmp, nums):
+            if not nums:
+                res.append(tmp)
+
+            for i, x in enumerate(nums):
+                dfs(tmp + [x], nums[:i] + nums[i + 1:])
+
+        dfs([], nums)
+        return res

0048.旋转图像/0048-旋转图像 2.py

@@ -0,0 +1,20 @@
+class Solution(object):
+    def rotate(self, matrix):
+        """
+        :type matrix: List[List[int]]
+        :rtype: None Do not return anything, modify matrix in-place instead.
+        """
+        #ÏÈתÖÃÔÙ×óÓҶԳƷ­×ª
+        if not matrix or not matrix[0]:
+            return matrix
+        n = len(matrix)
+
+        for i in range(n):
+            for j in range(i + 1, n):
+                matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
+
+        for row in matrix:
+            for i in range(n // 2):
+                row[i], row[n - 1 - i] = row[n - 1 - i], row[i]
+
+        return matrix