Updated the logic for early exit. Added missing condition for input

Fixed the issue with no input value.
Updated the logic for early exit for invalid patterns

identify_parenthesis_pattern.py

@@ -1,14 +1,17 @@
 def check_pattern(input_pattern):
     ## First check if the count of '(' and ')' are same. If not, return False. 
-    count_opening_braces = 0
-    count_closing_braces = 0
-    for char in input_pattern:
-        if char == '(':
-            count_opening_braces += 1
-        if char == ')':
-            count_closing_braces += 1
+    # count_opening_braces = 0
+    # count_closing_braces = 0
+    # for char in input_pattern:
+    #     if char == '(':
+    #         count_opening_braces += 1
+    #     if char == ')':
+    #         count_closing_braces += 1
 
-    if count_opening_braces != count_closing_braces:
+    # if count_opening_braces != count_closing_braces:
+    #     print("unequal number of open and closing braces in the pattern detected")
+    #     return False
+    if len(input_pattern) % 2 != 0:
         print("unequal number of open and closing braces in the pattern detected")
         return False
     else:
@@ -50,11 +53,14 @@ def check_pattern(input_pattern):
         # Inorder for the Github action to succed, Hardcoding the input with an example value.
         # Code verified with user prompted input already.
         #input_pattern = input("Enter the string pattern: ").strip()
-        input_pattern = "()()()()"
-        for char in input_pattern:
-            if char not in ('(', ')'):
-                raise ValueError("Only '(' and ')' allowed in the input pattern")
-        checked_result = check_pattern(input_pattern)
-        print(checked_result)
+        input_pattern = "()()()"
+        if input_pattern:
+            for char in input_pattern:
+                if char not in ('(', ')'):
+                    raise ValueError("Only '(' and ')' allowed in the input pattern")
+            checked_result = check_pattern(input_pattern)
+            print(checked_result)
+        else:
+            raise ValueError("Only '(' and ')' allowed in the input pattern")
     except ValueError as e:
         print(f"{e.args[0]}")